Problem Solver
For my problem, the q2 that was given to me was .06.
Now the steps I went through to solve my problem were:
- I had been given .06 as my q2, therefore I was able to find q.
- Once I found q I decided to use the formula 1-q=p to find p.
- When I reached to find p I then of course squared it to find p2.
- After I had found what the variables for p & q were I was able to find the heterozygous which is 2xpxq.
- After all that identification, I was able to contain the number of individuals by multiplying the homozygous recessive individual (q2), homozygous dominant individual (p2), and the heterozygous individual (2pq) by 1000 because that was the population.
- I then looked at the results of number of of allies each factor had in terms of percentage.
***Remember I was given p2 as .06 and theirs 1000 individuals in a population.
q2= .06
q= .245 (1-q=p)
p= .755. 1-.245=.755=P
p2= .5700.
2pq= .36995
# of individuals:
q2- 1000(.06)= 60 homo. recessive individuals
p2- 1000(.5700)= 570.0 homo. dominant individual
2pq- 1000(.36995)= 369.95 as 370 heterozygous individuals
60+570+370= 1000 individuals in population.
# of alleles:
24.5% of the alleles are recessive
75.5% of the alleles are dominant
6% of the alleles are homozygous recessive
57% of the alleles are homozygous dominant
37% of the alleles are heterozygous
Your answer is well structured and I like how you listed the steps and it was easy to understand what you did . Overall it was great
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